Question 581166
f(x)=x^2 - 12x - 1, I am assuming this is what you meant to write:

vertex form, complete the square:

f(x) = x^2 -12x + 36 -1 -36

f(x) = (x - 6)^2 -37

Vertex = (6,-37)

upward facing parabola, max=infinity, minimum @ vertex (6,-37)

f'(x) = 2x -12 = 0
x=6

range = [-37, infinity)



{{{ graph( 900, 900, -10, 20, -40, 50, x^2 - 12x - 1) }}}