Question 581124
x1		y1	x2	y2				
5		6	1	3				
								
slope m =		(y2-y1)/(x2-x1)						
(	3	-	6	)/(	1	-	5	)
(	-3	/	-4	)  				
m=		 3/4						 
The required line passes through both the points. So we select one point and plug it with the slope 								
Plug value of  the slope  and point(	1	,	3	) in	
Y	=	m	x	+	b			
3.00	=	 3/4	*	1	+	b		
								
b=	3    	-	 3/4					
b=	9/ 4							
So the equation  will be								
Y 	=	 3/4	x	+	9/4			
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