<PRE><B>Question 580993</B>
Consider a box which has 7 red balls and 4 green balls: 
a. Find the probability of drawing a red ball on the first draw and a green ball on the second draw, if you do not return the first ball to the box.
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P(green | red) = (7/11)(4/10) = 14/55
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b. Find the probability of drawing a green ball on the first draw and a green ball on the second draw, if you do return the first ball to the box.
P(green | green) = (4/11)^2 = 16/121
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Cheers,
Stan H. 
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