Question 54922
The monthly revenue from the sale of this product is given by 
R = -0.08p^2 + 300p 
Revenue is the product of "p" and the demand (quantity sold). 
a.) Factor out the price on the right-hand side of the formula
R=p(-0.08p+300) 
b.) What is an expression of the monthly demand?
D=-0.08p+300 
c.) What is the monthly demand for this pool when the price is $3000?
D(3000)=-0.08(3000)+300
D(3000)=240+300=540 
d.) What is the approximate maximum revenue?
Maximum at -b/2a where a=-0.08, b=300
Max at -300/(-0.16)= 1875
R(1875)= -0.08(1875)^2+300(1875)=$281,250 (Maximum Revenue)
Cheers,
Stan H.