<PRE><B>Question 580754</B>
The equation x / x+2 + 3x+2 / x^2 + 2x = 3 / x has how many integer solutions? 
The solutions says: 
Find LCM = (x)(x+2). 
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x/(x+2) + (3x+2)/(x(x+2)) = 3/x
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Multiply thru by the LCM
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x^2 + 3x+2 = 3(x+2)
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x^2 + 3x + 2 = 3x + 6
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x^2 -4 = 0
(x-2)(x+2) = 0
Possible solution: x = 2 or x = -2
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But x  cannot be -2 as that would make the denominator
of the original problem be zero.
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Only solution: x = 2
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Cheers,
Stan H.</PRE>