Question 580434
Ia is the tens digit and b is the ones digit:
The number is
{{{10a+b=7(a+b)}}}
The number with the digits in reverse order is
{{{10b+4=4(a+b)}}}
Unfortunately, both equations simplify to {{{a=2b}}}, and there would be infinite solutions for that equation. However, a and b are digits, so the solutions are limited to (a,b) being (2,1), (4,2), (6,3), and (8,4).
@!,42,63, and 84 are all solutions