Question 580188


{{{5x+2y=6}}} Start with the given equation.



{{{2y=6-5x}}} Subtract {{{5x}}} from both sides.



{{{2y=-5x+6}}} Rearrange the terms.



{{{y=(-5x+6)/(2)}}} Divide both sides by {{{2}}} to isolate y.



{{{y=((-5)/(2))x+(6)/(2)}}} Break up the fraction.



{{{y=-(5/2)x+3}}} Reduce.



So the equation {{{y=-(5/2)x+3}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=-5/2}}} and the y-intercept is {{{b=3}}} note: the y-intercept is the point *[Tex \LARGE \left(0,3\right)]