Question 579984
Wrong, it's not x=-5/3

{{{36^(5x-2) = (1/6)^(11-x)}}}
{{{(6^2)^(5x-2) = (6^-1)^(11-x)}}} take log(base 6) of both sides

10x - 4 = -11 + x

9x = -7

x = -7/9

CHECK:

5(-7/9)-2 = -53/9
11 - (-7/9) = 106/9
<p>
{{{36^(-53/9) = 6.84 * 10^-10}}}
{{{(1/6)^(106/9) = 6.84 * 10^-10}}}