<PRE><B>Question 579965</B>
Two basketball players, A and B, have probabilities of .8 and .7 of making a shot on any given trial, respectively. Assume that the events are independent. If A and B shoot twice (each), what is the probability that at least 1 shot will be made? 
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P(at least one made) = 1 - P(both shooters miss 2 shots)
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= 1 - [0.2^2+0.3^2] 
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= 1 - [0.04+0.09]
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= 1 - [0.13]
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= 0.87
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Cheers,
Stan H.</PRE>