Question 579894
angle of elevation = 57 deg 27 mins

distance from the window = 38 m
let the height of office be h

Let the vertical heightbetween the window and the office be x feet.

height of office upto level of window= 
Tan 57 27' = x/38

angle of depression is 18 10'

vertical height of window from the ground = (h-x)

Tan 18  10' = (h-x)/38

Tan 57 27'+Tan 18  10' = (h-x)/38 + x/38

Tan 57 27'+Tan 18  10'= h/38 -x/38 +x/38

Tan 57 27'+Tan 18  10' = h/38

Tan 57.45 + Tan 18.17 = h/38

1.57 + 0.33 = h/38

1.9= h/38

h= 1.9 *38

h= 72.2 m

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From point A angle of elevation = 30 deg
From point B angle of elevation = 22 deg

distance AB = 50 ft.

let height of tree be h
and distance from point A be x

Tan 30 = h/x
Cot 30 = x/h

Point B
Tan 22 = h/(50+x)
cot 22 = (50+x)/h

Cot 22- Cot 30 = 50/h +x/h - x/h

2.475-1.733= 50/h

0.742= 50/h

h= 50/0.742

67.38 feet