Question 579426
I'll call the answer {{{x}}} Volts.
{{{primary/secondary=4/1=460/x}}}
So we start with
{{{4/1=460/x}}} , and solve for {{{x}}}
We could say the we multiply both sides times {{{x}}},
or we could say that the teacher (or the book) says that in proportions the cross products are equal (or something like that)
Anyway, we conclude that the following is an equivalent equation
{{{4x=460}}}
Then we could say that we divide both sides by 4 to get
{{{4x/4=460/4}}} --> {{{x=115}}}
So the secondary voltage is {{{highlight(115)}}} Volts.