Question 579792
They are saying that
( area ) = ( length ) x ( height )
given:
Area = {{{ 24x^5*y^3 }}}
Height = {{{ 8x^2*y^2 }}}
Let {{{ L }}} = length
-----------
{{{ 24x^5*y^3 = L*8x^2*y^2 }}}
If you divide both sides of an equation by the same
thing, then the equation is still true, that is the
left side still equals the right side. 
That means I can divide both sides by {{{ 8x^2*y^2 }}}
{{{ ( 24x^5*y^3 ) / ( 8x^2*y^2 ) = L*( 8x^2*y^2 ) / ( 8x^2*y^2 ) }}}
On the right side, everything cancels except {{{ L }}}, so
now I can say:
{{{ ( 24x^5*y^3 ) / ( 8x^2*y^2 ) = L }}}
Now I just have to do the division on the left side
This is a division of products. I can express it as 
products of divisions to simplify it.
{{{ ( 24/8 )*( x^5/x^2 )*( y^3/y^2 ) = L }}}
Now you just have to know how to handle exponents
I'll rewrite everything in long form
{{{ 3*(( x*x*x*x*x )/( x*x ))*(( y*y*y ) / ( y*y )) = L }}}
Now do the cancellations:
{{{ 3*( x*x*x )*y  = L }}}
Finally, I put {{{L}}} on the left and say {{{ x*x*x = x^3 }}}
{{{ L = 3x^3*y }}}
Hope this helps