<PRE><B>Question 579324</B>
The probability that a bulb produced by a factory will fuse after certain period of time is 0.05. Find the probability that out of 5 such bulbs
a. P(None fuses) = 0.95^5 = 0.7738
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b. P(Not more than 2 fuse) = binomcdf(5,0.05,2) = 0.9988
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c. P(More than 2 fuse) = 1-0.9988 = 0.0012
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Cheers,
Stan H.
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