Question 579216
.A(8,4)B(-4,14)

First find the midpoint co ordinates (x,y)
x= (x1+x2)/2
y=(y1+y2)/2

x=(8-4)/2 = 2
y= (14+4)/2 = 9

The perpendicular bisector passes through (2,9)

Find the slope of the line, A(8,4)B(-4,14)

x1		y1	x2	y2				
8		4	-4	14				
								
slope m =	(y2-y1)/(x2-x1)						
(14-4)/(-4-8)
(	10	/	-12	)  				
m=		-  5/ 6		

the line perpendicular to this line will have a slope of (6/5) ( negative reciprocal)
The slope of the perpendicular line is (6/5) and it passes through (2,9)
m=		6/ 5					
							
Plug value of  the slope  and point(	2 ,	9	) in
y=mx+b							
9.00	=	6/5	*	2    	+b		
b=	9-12/5				
							
b=	33/ 5						
So the equation  will be							
Y 	=	6/5	x	+	33/5	
	
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