Question 578748
To get rid of the complex term in the denominator, multiply top and bottom by the conjugate (9-2i)

{{{(7-4i)/(9+2i) * (9-2i)/(9-2i)}}}

That gives us 81 - 4(i^2) = 81 + 4 = 85 in the denominator

In the numerator, use Use FOIL:

(7-4i)(9-2i) = 63 -14i -36i +8i^2;   i^2=-1, so:

= 63 - 50i - 8 = 55 - 50i

{{{(55-50i)/(85)}}}    Divide through by 5

{{{(11-10i)/(17)}}}