Question 578223
{{{5/((e-2))}}} - {{{5/((2-e))}}}
we can factor out -1 from the 2nd denominator and have:
{{{5/((e-2))}}} - {{{5/(-1(e-2))}}}
dividing by -1 changes the sign so we have the same denominators, just add the terms
{{{5/((e-2))}}} + {{{5/((e-2)))}}} = {{{10/((e-2))}}}