Question 578269
Please help me solve this equation dividing(6x^2y^2+4x^4y^6-4x^5y^3)/(2x^2y^2)
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That's not an equation.
I can tell, there's no equal sign.
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{{{(6x^2y^2+4x^4y^6-4x^5y^3)/(2x^2y^2)}}}
Cancel whatever you can.  NUM and DEN have an x
 = {{{(6xy^2+4x^3y^6-4x^4y^3)/(2xy^2)}}}
They still have an x
 = {{{(6y^2+4x^2y^6-4x^3y^3)/(2y^2)}}}
No more x's
 = {{{(6y^2+4x^2y^6-4x^3y^3)/(2y^2)}}}
Cancel some 2's
 = {{{(3y^2 + 2x^2y^6 - 2x^3y^3)/(y^2)}}}
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then y^2
 = {{{(3 + 2x^2y^4 - 2x^3y)}}}
Looks like we're done.