Question 54812
The length of a rectangle is 2 in. more than twice its width.  If the perimeter of the rectangle is 52 in., find the width of the rectangle.
 You're almost right.
Let the width =x
then the length=2x+2
The perimeter=52 in.
The formula for the perimeter of a rectangle is: {{{highlight(P=2W+2L)}}} where P=perimeter, W=width, and L=length.
P=52, W=x, and L=2x+2
52=2(x)+2(2x+2)
52=2x+4x+4
52=6x+4
52-4=6x+4-4
48=6x
48/6=6x/6
8=x
The width:x=8 in.
Happy Calculating!!!