Question 54812
The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 52 in., find the width of the rectangle.
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Let the width be "x"
Length = 2x+2
Perimeter = 2(length + width)
52 = 2(3x+2)
26=3x+2
3x=24
x=8
width = 8 inches
Cheers,
Stan H.