Question 578197
{{{ b = 100*2^t }}}
given:
{{{ b = 51200 }}}
{{{ 51200 = 100*2^t }}}
{{{ 512 = 2^t }}}
I noted that {{{ 2*2*2*2*2*2*2*2*2 = 512 }}}
{{{ 512 = 2^9 }}}, so
{{{ 2^9 = 2^t }}}
{{{ t = 9 }}}
Every period of length {{{ t }}} is 15 min, so
{{{ 9*15 = 135 }}} 
It takes 135 minutes