Question 577882


{{{(x+5)(2x+7)}}} Start with the given expression.



Now let's FOIL the expression.



Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(x)+5)(highlight(2x)+7)}}} Multiply the <font color="red">F</font>irst terms:{{{(x)*(2*x)=2*x^2}}}.



{{{(highlight(x)+5)(2x+highlight(7))}}} Multiply the <font color="red">O</font>uter terms:{{{(x)*(7)=7*x}}}.



{{{(x+highlight(5))(highlight(2x)+7)}}} Multiply the <font color="red">I</font>nner terms:{{{(5)*(2*x)=10*x}}}.



{{{(x+highlight(5))(2x+highlight(7))}}} Multiply the <font color="red">L</font>ast terms:{{{(5)*(7)=35}}}.



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So we have the terms: {{{2*x^2}}}, {{{7*x}}}, {{{10*x}}}, {{{35}}} 



{{{2*x^2+7*x+10*x+35}}} Now add every term listed above to make a single expression.



{{{2x^2+17x+35}}} Now combine like terms.



So {{{(x+5)(2x+7)}}} FOILs to {{{2x^2+17x+35}}}.



In other words, {{{(x+5)(2x+7)=2x^2+17x+35}}}.


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