Question 54843
How much water should be added to 8 ML of 6% Saline solution to reduce the concentration to 4%?
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Amount of 6% solution is 8ML.
Amount of active ingredient is 0.06(8)= 0.48ML
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Amount of water to add is "x"ML
Amount of active ingredient is 0ML
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Amount of mixed solution is "8+x"ML
Amount of active ingredient is 0.04(8+x)= 0.32+0.4x
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EQUATION:
active ingre. + active ingre. = active ingre
0.48 + 0 = 0.32 + 0.04x
0.16 = 0.04x
x=4ML (amount of water that must be added)
Cheers,
Stan H.