Question 577839
From original problem:

Original rectangle:  L = 2W

A(original) = length x width = (2W)(W) = 2W^2 

When L-4 and W-3, A(original) is less 88 in^2

L-4 = 2W-4 so:

(2W-4)(W-3) = 2W^2 - 88

2W^2 - 4W - 6W + 12 = 2W^2 - 88         (2W^2 cancels out 

12 - 10W = -88

10W = 100

W = 10
L = 2W = 20

Check:

A(original) = L x W = 20 x 10 = 200 square inches

A(new) = (L-4)(W-3) = 16 x 7 = 112 square inches

200 - 112 = 88 square inches √