Question 577326
Two ways to do it:


Recognize that 42 = 14*3 and 14+3 = 17. Therefore X and Y are 14 and 3.


The other solution is to say that *[tex \LARGE Y = 17-X]. Substituting into the first equation you will get *[tex \LARGE X(17-X) = 42]. Solve the quadratic. You should get X = 3 or X = 14 (which makes sense since X and Y are symmetric and they lead to the same solution).