Question 577612
Let x= hours day 1
Let y= hours day 2
Let z= hours day 3

x+y+z=2196

day 1= 64x
day 2= 62y
day 3= 58z



x+y+z=36
y=36-x-z

64x+62y+58z= 2196

64x+62(36-x-z)+58z= 2196
64x+62*36-62x-62z+58z=2196
2x-4z=-2232+2196
2x-4z=-36

Now z= x+4
2x-4(x+4)=-36
2x-4x-16=-36
-2x=-20
/-2
x=10 hours  first day
z=x+4 = 14 hours
y=12 hours