Question 577464
find three consecutive odd integers such that three times the third is seventeen more than the sum of the first and second one.
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
3(2x+3) = 4x+17
6x+9 = 4x+17
2x = 8
x = 4
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1st: 2x-1 = 7
2nd:  9
3rd: 11
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Cheers,
Stan H.