Question 577235
Given that the random variable X is normally distributed with a mean of 80 and a standard deviation of 10, P(85 ≤ X ≤ 90) is:
a. 0.5328 
b. 0.1498 
c. 0.5841 
d. 0.3413 
e. 0.1915 

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z(85) = (85-80)/10 = 5/10 = 1/2
z(90) = (90-80)/10 = 10/10 = 1
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P(85<= x <=90) = P(1/2<= z <=1) = normalcdf(1/2,1) = 0.1499
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Cheers,
Stan H.
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