Question 577034
a=b+3(4-c)


a=5+3(4-2)


a=5+3(2)


a=5+6


a=11


So the answer is a = 11

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I'm assuming you want to find the zeros of y=3(x+5)(x-2)


y=3(x+5)(x-2)


0=3(x+5)(x-2)


3(x+5)(x-2)=0


x+5=0 or x-2=0


x = -5 or  x = 2



So the solutions are x = -5 or  x = 2