Question 576893
THE SIMPLE WAY
The problem did not give any numbers for A and B because it does not matter what they are. The answer would be the same for any B, as long as "20% of A is the 30% of B."
So we set up a convenient B.
If B was 100, 30% of B would be 30, and that would be 20% (or 1/5) of A.
So A would be 5 times 30, or 150, which is 150% of the 100 that we assumed B to be.
THE ALGEBRA WAY
20% of A is {{{0.20*A}}}
30% of B is {{{0.30*B}}}
We know that {{{0.20*A=0.30*B}}}
What percent of B is A? Let's find out what fraction of B is A
{{{0.20*A=0.30*B}}} --> {{{0.20*A/0.20=0.30*B/0.20}}} --> {{{A=(0.30/0.20)*B}}} --> {{{A=1.5*B}}} --> {{{A/B=1.5*B/B}}} -->  {{{A/B=1.5}}} --> {{{A/B=150/100}}}
So A is 150% of B.