Question 576714
what is the base of a right triangle with a height of 5 and a hypotenuse of 8?
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Got old Pythagoras out of bed for this one: a^2 + b^2 = c^2
5^2 + b^2 = 8^2
25 + b^2 = 64
b^2 = 64 - 25
b^2 = 39
b = {{{sqrt(39)}}}
b ~ 6.245 is the base
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You can check this on your calc: enter {{{sqrt(5^2+6.245^2)}}}