Question 576653
Simplify:
{{{(z^2+6z+9)/(z^2-z-12)}}} Factor the numerator and the denominator.
{{{cross((z+3))(z+3)/cross((z+3))(z-4)}}} Now cancel the ({{{z+3}}})'s as indicated leaving you with.
{{{(z+3)/(z-4)}}}