Question 576649
<pre>
(x³ + 3) divided by (x - 1)

First put placeholder terms for the 2nd and 1st powers of x:

 x³ + 0x² + 0x - 1

Then 

1 | 1 0 0 3
  |<u>   1 1 1</u>
    1 1 1 4

answer: 1x² + 1x + 1 + {{{4/(x-1)}}} or just

          x² + x + 1 + {{{4/(x-1)}}}

Edwin</pre>