Question 576659
p(M<10.1); n=100
calculate the probability with Mu=10 and the standard deviation = 3. I know that z=.33 and p=.6293; however, I am not sure of the steps to get this answer. please assist.
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P(M < 10.1)
z(10.1) = (10.1-10)/3 = 0.1/3 = 1/30 = 0.0333
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P(z > 0.0333) = normalcdf(0.0333,100) = 0.4867
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Cheers,
Stan H.