<PRE><B>Question 576656</B>
If a committee of 5 is to be chosen from 10 workers, what is the probability that it must include at least 2 women? 
(There are 5 men and 5 women)
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# of ways to choose at least 2 women: 5C2 + 5C3 + 5C4 + 5C5 = 10+10+5+1 = 26
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# of random ways to select 5 randomly: 10C5 = 252
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P(at least 2 woman) = 26/252 = 13/126
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Cheers,
Stan H.
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