Question 576419
Please help me solve this problem: 
Sheila visits the dentist once per year. After her check-ups, she may choose one toy out of 8 different toys. Over 6 years, how many ways can Sheila choose her toys if she chooses a different toy each year?
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Ans: 8P6 = 8!/(2!) = 8*7*6*5*4*3 = 20160
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Cheers,
Stan H.