Question 54761
3(2x - 4) - 4x < 2x + 3
or 6x - 12 - 4x < 2x + 3
or 2x - 12 < 2x + 3
or 2x - 12 - 2x < 2x + 3 - 2x [assuming x > 0]
or -12 < 3 which is always true when x>0
So the solution is x>0.