Question 54758
What is the equation of the line having slope 4/7 and passing through the point (-3,1) in standard form?
You are given a slope (m) and a point (x1,y1) and are being asked for the equation of a line, so you need to use the point-slope formula.{{{highlight(y-y1=m(x-x1))}}}
The standard form of a line is {{{highlight(Ax+By=C)}}} A,B, and C are integers and in most books A is positive.
:
Your slope(m)=4/7 and your point (x1,y1)=(-3,1)
{{{y-1=(4/7)(x-(-3))}}}
{{{y-1=(4/7)(x+3)}}}
{{{7(y-1)=7(4/7)(x+3)}}}
{{{7y-7=cross(7)(4/cross(7))(x+3)}}}
{{{7y-7=4(x+3)}}}
{{{7y-7=4x+12}}}
{{{-4x+7y-7=-4x+4x+12}}}
{{{-4x+7y-7+7=12+7}}}
{{{-4x+7y=19}}}
{{{-(-4x+7y)=-(19)}}}
{{{4x-7y=-19}}}
Happy Calculating!!!