Question 575674
A basket contains 3 red,4 white and 7 yellow beads. Three beads are taken at random without replacement. Calculate the probability of getting
i. Three beads of the same colour (2 marks)
# of ways to succeed: 3C3+4C3+7C3 = 1 + 4 + 35 = 40
# of random results: 14C3 = 364
P(3 same color) = 40/364
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ii. At least two white beads (2marks)
# of ways to succeed: 4C2 + 4C3 + 4C4 = 6 + 4 + 1 = 11
# of random results: 364
P(at least 2 white) = 11/364
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iii) A red bead followed by a yellow bead. (3marks)
P(yellow | red) = (3/14)(7/13) = 3/26
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Cheers,
Stan H.
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