<PRE><B>Question 575508</B>
4 blue balls, 3 red ones and 1 white one. If you draw two balls without replacing the first one, what is the probability that the first ball is red and the second is white?
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# of ways to draw red and then white: 3*1 = 3
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# of random pairs: 8C2 = 8*7/1*2 = 28
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P(red/white) = 3/28
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Cheers,
Stan h.</PRE>