Question 575368
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Let *[tex \LARGE x] represent the cost of a brass part and *[tex \LARGE y] represent the cost of a steel part.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ +\ 10y\ =\ 48]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 7x\ +\ 7y\ =\ 54]


Did you leave out the number of steel parts for the second situation or is the quantity 7 and 7 like I've assumed?


Be that as it may, once you have the right coefficient on *[tex \LARGE y] in the second equation, then solve the 2X2 system.  Once you have values for *[tex \LARGE x] and *[tex \LARGE y], calculate *[tex \LARGE 10x\ +\ 13y]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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