<PRE><B>Question 575152</B>
A normal distribution has a mean of 80 and a standard deviation of 14. Compute the probability of a value between 75.0 and 90.0. 
a. .2022 
b. .3595 
c. .4017 
d. None of the above 
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Using a TI-84 you get:
normalcdf(75,90,80,14) = 0.4020
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Cheers,
Stan H.
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