Question 574896
(1/4x^2 - 2/3)*(1/4x - 1/4)
FOIL
multiply the 1st two terms F
1/4x^2 * 1/4x = (1/16)x^3
;
multiply the two outer terms O
1/4x^2 * - 1/4 = -(1/16)x^2
;
multiply the two inner terms I
-2/3 * 1/4x = -(2/12)x
;
multiply the last two terms L
-2/3 * -1/4 = (2/12)
:
Put them together;
{{{(1/16)x^3 - (1/16)x^2 - (2/12)x + (2/12)}}}
we can reduce the 12th fractions
{{{(1/16)x^3 - (1/16)x^2 - (1/6)x + (1/6)}}}