Question 574971


{{{x^3-7x^2-9x+63}}} Start with the given expression



{{{(x^3-7x^2)+(-9x+63)}}} Group the terms in two pairs



{{{x^2(x-7)-9(x-7)}}} Factor out the GCF {{{x^2}}} out of the first group. Factor out the GCF {{{-9}}} out of the second group



{{{(x^2-9)(x-7)}}} Since we have the common term {{{x-7}}}, we can combine like terms



{{{(x-3)(x+3)(x-7)}}} Now factor {{{x^2-9}}} to get {{{(x-3)(x+3)}}}



So {{{x^3-7x^2-9x+63}}} factors to {{{(x-3)(x+3)(x-7)}}}



In other words, {{{x^3-7x^2-9x+63=(x-3)(x+3)(x-7)}}}