Question 574831
<pre><font size = 5><b>
&#9856;&#9856;   <font color = "red">&#9856;&#9857;</font>   &#9856;&#9858;   &#9856;&#9859;   &#9856;&#9860;  &#9856;&#9861;

<font color = "red">&#9857;&#9856;</font>   &#9857;&#9857;   &#9857;&#9858;   &#9857;&#9859;   &#9857;&#9860;  &#9857;&#9861;

&#9858;&#9856;   &#9858;&#9857;   &#9858;&#9858;   &#9858;&#9859;   &#9858;&#9860;  &#9858;&#9861;

&#9859;&#9856;   &#9859;&#9857;   &#9859;&#9858;   &#9859;&#9859;   &#9859;&#9860;  &#9859;&#9861;

&#9860;&#9856;   &#9860;&#9857;   &#9860;&#9858;   &#9860;&#9859;   &#9860;&#9860;  &#9860;&#9861;

&#9861;&#9856;   &#9861;&#9857;   &#9861;&#9858;   &#9861;&#9859;   &#9861;&#9860;  &#9861;&#9861;
<font size = 3>
Above are the 36 ways the two dice can fall.  Those two 
I have colored red are the only ones that have sum 3.  
That's 2 out of 36, so the probability is {{{2/36}}} which
reduces to {{{1/18}}}.

Edwin</pre>