Question 574671
{{{3x+7=(4y/z)^2}}} 
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a. Solve for x
Get rid of the brackets, square everything inside the brackets
{{{3x+7=(16y^2)/z^2)}}}
Subtract 7 from both sides
3x = {{{(16y^2)/z^2-7}}}
divide both sides by 3
x = {{{(16y^2)/(3z^2)}}}-{{{7/3}}}
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b. solve for y
Get rid of the brackets, square everything inside the brackets
{{{3x+7=(16y^2)/z^2)}}}
multiply both sides by z^2
{{{3xz^2 + 7z^2 = 16y^2}}}
divide both sides by 16
{{{((3xz^2+7z^2))/16}}} = {{{y^2}}}
Find the square root of both sides
{{{sqrt(((3xz^2+7z^2))/16)}}} = y
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c. Solve for z
{{{3x+7=(16y^2)/z^2)}}}
multiply both sides by z^2
{{{z^2(3x + 7) = 16y^2}}}
divide both sides by (3x+7)
{{{z^2 = (16y^2)/(3x+7)}}}
Find the square root of both sides
z = {{{sqrt((16y^2)/(3x+7))}}}
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I know this seems like a lot to absorb, but take it one step at a time and understand what happened. Take your time to do this.   C