<PRE><B>Question 574684</B>
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You can&#39;t add a constant to *[tex \Large x^2\ +\ 14] and make a perfect square trinomial.  A perfect square trinomial has a first degree *[tex \Large x] term, so you would have to add a first degree *[tex \Large x] term, but that is not a constant.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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