Question 574586
Use the binomial probability formula


P(X = x) = (n C x)*(p)^(x)*(1-p)^(n-x) 


P(X = 4) = (20 C 4)*(0.1667)^(4)*(1-0.1667)^(20-4) 


P(X = 4) = (20 C 4)*(0.1667)^(4)*(0.8333)^(20-4) 


P(X = 4) = (4845)*(0.1667)^(4)*(0.8333)^16 


P(X = 4) = (4845)*(0.000772)*(0.054053) 


P(X = 4) = 0.202177



So the probability of getting exactly four two's is 0.202