Question 574501
1 = 1 = {{{1^2}}}
1+3 = 4 = {{{2^2}}}
1+3+5 = 9 = {{{3^2}}}
1+3+5+7 = 16 = {{{4^2}}}
...
The sum of the first n odd numbers is {{{n^2}}}.
The nth odd number is 2n-1.
2n-1 = 101
n = 51
There are 51 odd numbers from 1 to 101, inclusive.
The sum of the first 51 odd numbers is {{{51^2=2601}}}

Answer: 2601