Question 573951
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Unwrap the FOIL.


There are only a couple of ways to make *[tex \LARGE 14x^2] out of two factors each of which has an *[tex \LARGE x]; either *[tex \LARGE x] and *[tex \LARGE 14x] or *[tex \LARGE 2x] and *[tex \LARGE 7x].


So start with


*[tex \LARGE (x\ \pm\ \ )(14x\ \mp\ \ )]


and mess about with various integer factors of 84, 84 and 1, 42 and 2, 21 and 3, 14 and 6, or 7 and 12.  Nothing seems to work.


So try


*[tex \LARGE (2x\ \pm\ \ )(7x\ \mp\ \ )]


with all of those factors of 84.  Hmm...2 times 12 is 24 and -7 times 7 is -49 and 25 - 49 is -25.  That looks promising.  Let me know what you figured out.
  


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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