Question 573874
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A great circle of a sphere and the sphere have the same radius (that's what makes it a great circle).  The area of a circle of radius *[tex \Large r] is *[tex \Large \pi{r^2}].  The surface area of a sphere of radius *[tex \Large r] is *[tex \Large 4\pi{r^2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{A_{gc}}{A_s}\ =\ \frac{\pi{r^2}}{4\pi{r^2}}\ =\ \frac{1}{4}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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